# Divisors of 9993

## Divisors of 9993

The list of all positive divisors (that is, the list of all integers that divide 22) is as follows :

Accordingly:

9993 is multiplo of 1

9993 is multiplo of 3

9993 is multiplo of 3331

9993 has 3 positive divisors

## Parity of 9993

9993is an odd number,as it is not divisible by 2

## The factors for 9993

The factors for 9993 are all the numbers between -9993 and 9993 , which divide 9993 without leaving any remainder. Since 9993 divided by -9993 is an integer, -9993 is a factor of 9993 .

Since 9993 divided by -9993 is a whole number, -9993 is a factor of 9993

Since 9993 divided by -3331 is a whole number, -3331 is a factor of 9993

Since 9993 divided by -3 is a whole number, -3 is a factor of 9993

Since 9993 divided by -1 is a whole number, -1 is a factor of 9993

Since 9993 divided by 1 is a whole number, 1 is a factor of 9993

Since 9993 divided by 3 is a whole number, 3 is a factor of 9993

Since 9993 divided by 3331 is a whole number, 3331 is a factor of 9993

## What are the multiples of 9993?

Multiples of 9993 are all integers divisible by 9993 , i.e. the remainder of the full division by 9993 is zero. There are infinite multiples of 9993. The smallest multiples of 9993 are:

0 : in fact, 0 is divisible by any integer, so it is also a multiple of 9993 since 0 × 9993 = 0

9993 : in fact, 9993 is a multiple of itself, since 9993 is divisible by 9993 (it was 9993 / 9993 = 1, so the rest of this division is zero)

19986: in fact, 19986 = 9993 × 2

29979: in fact, 29979 = 9993 × 3

39972: in fact, 39972 = 9993 × 4

49965: in fact, 49965 = 9993 × 5

etc.

## Is 9993 a prime number?

It is possible to determine using mathematical techniques whether an integer is prime or not.

for 9993, the answer is: No, 9993 is not a prime number.

## How do you determine if a number is prime?

To know the primality of an integer, we can use several algorithms. The most naive is to try all divisors below the number you want to know if it is prime (in our case 9993). We can already eliminate even numbers bigger than 2 (then 4 , 6 , 8 ...). Besides, we can stop at the square root of the number in question (here 99.965 ). Historically, the Eratosthenes screen (which dates back to Antiquity) uses this technique relatively effectively.

More modern techniques include the Atkin screen, probabilistic tests, or the cyclotomic test.