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In addition we can say of the number **530 that it is even**

530 is an even number, as it is divisible by 2 : 530/2 = 265

The factors for 530 are all the numbers between -530 and 530 , which divide 530 without leaving any remainder. Since 530 divided by -530 is an integer, -530 is a factor of 530 .

Since 530 divided by -530 is a whole number, -530 is a factor of 530

Since 530 divided by -265 is a whole number, -265 is a factor of 530

Since 530 divided by -106 is a whole number, -106 is a factor of 530

Since 530 divided by -53 is a whole number, -53 is a factor of 530

Since 530 divided by -10 is a whole number, -10 is a factor of 530

Since 530 divided by -5 is a whole number, -5 is a factor of 530

Since 530 divided by -2 is a whole number, -2 is a factor of 530

Since 530 divided by -1 is a whole number, -1 is a factor of 530

Since 530 divided by 1 is a whole number, 1 is a factor of 530

Since 530 divided by 2 is a whole number, 2 is a factor of 530

Since 530 divided by 5 is a whole number, 5 is a factor of 530

Since 530 divided by 10 is a whole number, 10 is a factor of 530

Since 530 divided by 53 is a whole number, 53 is a factor of 530

Since 530 divided by 106 is a whole number, 106 is a factor of 530

Since 530 divided by 265 is a whole number, 265 is a factor of 530

Multiples of 530 are all integers divisible by 530 , i.e. the remainder of the full division by 530 is zero. There are infinite multiples of 530. The smallest multiples of 530 are:

0 : in fact, 0 is divisible by any integer, so it is also a multiple of 530 since 0 × 530 = 0

530 : in fact, 530 is a multiple of itself, since 530 is divisible by 530 (it was 530 / 530 = 1, so the rest of this division is zero)

etc.

It is possible to determine using mathematical techniques whether an integer is prime or not.

for 530, the answer is:
**No, 530 is not a prime number**.

To know the primality of an integer, we can use several algorithms. The most naive is to try all divisors below the number you want to know if it is prime (in our case 530). We can already eliminate even numbers bigger than 2 (then 4 , 6 , 8 ...). Besides, we can stop at the square root of the number in question (here 23.022 ). Historically, the Eratosthenes screen (which dates back to Antiquity) uses this technique relatively effectively.

More modern techniques include the Atkin screen, probabilistic tests, or the cyclotomic test.

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